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Hill sphere

Ch. 1 of 6
— CH. 1 · INTRODUCTION —

Contents

Hill sphere

6 sections
  • The Hill sphere of the 104-ton Space Shuttle, orbiting 300 km above Earth, measured just 120 centimeters in radius. That radius was smaller than the Shuttle itself, meaning no object could have maintained a stable orbit around it. The Hill sphere is the region around any astronomical body where that body's own gravity outranks every more massive neighbor nearby. American astronomer George William Hill gave the concept its formal mathematical definition, building on earlier work by the French astronomer Édouard Roche. What determines the size of that gravitational territory? Why does a distant planet command a Hill sphere hundreds of millions of kilometers wide while a spacecraft can hold almost nothing? Their mathematical framework, drawn from the mechanics of three interacting bodies, converted an intuitive concept into a precisely defined boundary.

  • De Pater and Lissauer noted that all bodies within a gravitational system feel each other's pull. When only two objects interact, the mathematics yields an exact analytic solution. Physicists call that case "completely integrable," meaning one independent integral exists per degree of freedom. The moment a third body of comparable mass enters the picture, that clean solution vanishes. According to de Pater and Lissauer, three or more interacting bodies "cannot be deduced analytically"; their future positions require numerical integration instead. The one useful exception is when the third body has negligible mass, a case formally known as the restricted three-body problem. That approximation is the mathematical home of the Hill sphere.

    The Jacobi integral defines a zero-velocity surface in three-body space that no object can cross unless it gains enough energy. When an object's energy is low, this surface completely surrounds the smaller body. As energy rises, gaps open at the Lagrange points, allowing escape. At the exact threshold between these two states, the surface narrows to a cone-like point at the nearest Lagrange point. Beyond that edge, the primary body's tidal forces grow dominant. Any object straying past it would gradually drift into orbit around the more massive body. Earth's own Hill sphere offers a familiar test case, with every ingredient of the formula already measured precisely.

  • Earth circles the Sun at 149.6 million km, precisely one astronomical unit. That orbital distance is one of the key inputs into the Hill sphere formula. The result for Earth is a gravitational zone extending roughly 1.5 million km, or 0.01 AU, in every direction. The Moon orbits at about 0.384 million km, well within that zone. That positioning is why the Moon stays with Earth rather than wandering into an independent orbit around the Sun.

    In the Sun's direction, the Hill sphere reaches its narrowest, where the Sun's pull most directly counteracts Earth's gravity. An object nudged past that limit would spend part of each orbit outside Earth's gravitational zone. The Sun's gravity would then gradually pull the object into a solar orbit.

    At 230,000 AU, the Sun's own Hill sphere has an unstable maximum extent. That limit is set not by any planet but by gravitational competition from the galactic nucleus and nearby massive stars. One way astronomers define the Solar System's true outer edge is to place it at that maximum. Among the Solar System's planets, the ranking of Hill spheres defies the obvious expectation.

  • Neptune claims the widest Hill sphere of any planet in the Solar System, reaching 116 million km. Jupiter, far more massive than Neptune, manages only 53 million km. The reason is orbital distance. Neptune's remote position means the Sun exerts far weaker tidal forces on its Hill sphere than on Jupiter's closer orbit. That reduction in tidal pressure outweighs Jupiter's greater mass.

    Planet Nine, a hypothetical world not yet confirmed, would dwarf even Neptune's reach. Its estimated mass is near 10 Earth masses, its physical radius near 15,000 km. An orbit around 500 AU from the Sun, with an eccentricity near 0.25, would yield a Hill sphere of roughly 1.2 billion km. That figure is more than ten times Neptune's Hill radius. Whether a moon occupies any part of a Hill sphere depends not only on its distance but on which direction it travels.

  • Jupiter's outer moon population is lopsided, with retrograde satellites far outnumbering prograde ones. At large distances from a primary body, retrograde orbits remain stable across a wider portion of the Hill sphere than prograde orbits do. A retrograde moon travels opposite to the planet's direction around the Sun. That geometry reduces the disruptive tidal forces the parent star can exert on the moon's orbit. Saturn's moon population, by contrast, is a more even mix of retrograde and prograde orbits, suggesting that other factors complicate the picture.

    Ten mutual Hill radii is the critical separation for neighboring planets in a system of three or more bodies to avoid destabilizing each other. When two adjacent planets fall within that distance, the configuration is inherently unstable. A third planet introduces perturbations that drain angular momentum from the system, and that loss eventually forces a gravitational reorganization. At the smallest scales, some bodies hold Hill spheres measured in kilometers rather than millions, yet they still manage to host moons.

  • HD 209458 b, a hot Jupiter orbiting another star, has a Hill sphere radius of 593,000 km. That is roughly eight times the planet's own physical radius of about 71,000 km. CoRoT-7b, the smallest known close-in extrasolar planet, has a Hill sphere of about 61,000 km. That is roughly six times its physical radius of around 10,000 km. Both planets could theoretically support small moons, provided those moons orbit outside each body's Roche limit.

    66391 Moshup, a Mercury-crossing asteroid, carries its own moon, named Squannit, within a Hill sphere just 22 km in radius. The asteroid 1 Ceres can have a Hill sphere reaching up to 220,000 km in radius. The gap between these two cases is a direct measure of how sharply the Hill sphere contracts with mass.

    In low Earth orbit, a spherical body must be denser than lead to fit inside its own Hill sphere. Without that density, the body cannot support any stable satellite. Move to geostationary orbit and the requirement drops to just over 6 percent the density of water. Even meeting that threshold is no guarantee of permanence. Radiation pressure can push objects across the Hill sphere's boundary. So can the Yarkovsky effect, a small thermal force on rotating bodies caused by the asymmetric absorption and re-emission of sunlight. Moshup's Hill sphere spans just 22 km. At that scale, even a faint push from radiation pressure could, over cosmic timescales, free its moon Squannit.

Updated

Common questions

Who defined the Hill sphere and what was it based on?

The Hill sphere was defined by American astronomer George William Hill, drawing on earlier work by the French astronomer Édouard Roche. The concept emerged from the restricted three-body problem, which treats one of three interacting bodies as having negligible mass.

What is the size of Earth's Hill sphere?

Earth's Hill sphere extends roughly 1.5 million km, or 0.01 AU, in radius. The Moon orbits at about 0.384 million km from Earth, placing it comfortably within this gravitational zone.

Why does Neptune have a larger Hill sphere than Jupiter?

Neptune's Hill sphere reaches about 116 million km, larger than Jupiter's 53 million km, because Neptune orbits so far from the Sun that the Sun's tidal forces barely squeeze its gravitational domain. Greater distance from the parent star enlarges the Hill sphere more effectively than greater mass alone.

Why are retrograde orbits more stable within a Hill sphere than prograde orbits?

At large distances from a primary body, retrograde orbits remain stable across a wider region of the Hill sphere than prograde orbits. A retrograde moon travels opposite to the planet's orbital direction around the Sun, reducing the tidal disruption the parent star can impose on its orbit.

Can asteroids have their own moons within their Hill spheres?

Yes. The asteroid 66391 Moshup, a Mercury-crossing asteroid, hosts its own moon named Squannit within a Hill sphere just 22 km in radius. The asteroid 1 Ceres can have a Hill sphere reaching up to 220,000 km.

What would be the Hill sphere of hypothetical Planet Nine?

If Planet Nine exists with a mass near 10 Earth masses, a physical radius near 15,000 km, and an orbit around 500 AU from the Sun with an eccentricity near 0.25, its Hill sphere would span roughly 1.2 billion km. That is more than ten times the Hill radius of Neptune.

All sources

17 references cited across the entry

  1. 1JournalOn the local and global properties of gravitational spheres of influenceD. Souami et al. — 2020
  2. 2How Many Moons Does Mercury Have?Matt Williams — 2015-12-30
  3. 3JournalGravitational clearing of natural satellite orbitsRoderick J. Hill — Cambridge University Press — 2022
  4. 4JournalOn the Dynamical Limits of the Solar SystemG. A. Chebotarev — March 1965
  5. 5Word of the Week: Hill SphereLauretta, Dante and the Staff of the Osiris-Rex Asteroid Sample Return Mission — University of Arizona — 2023
  6. 6BookPlanetary Sciencesde Pater, Imke & Lissauer, Jack — Cambridge University Press — 2015
  7. 7JournalTemporary Capture of Asteroids by an Eccentric PlanetHiguchi1, A. & Ida, S. — The American Astronomical Society — April 2017
  8. 8JournalOrbital Stability Zones About Asteroids: II. The Destabilizing Effects of Eccentric Orbits and of Solar RadiationHamilton, D.P. & Burns, J.A. — Academic Press — March 1992
  9. 9Ever Decreasing CirclesFollows, Mike — 4 October 2017
  10. 10JournalGravitational Spheres of the Major Planets, Moon and SunG. A. Chebotarev — 1964
  11. 12JournalChaos-assisted capture of irregular moonsSergey A. Astakhov et al. — 2003
  12. 14(66391) Moshup and SquannitRobert Johnston — 20 October 2019

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